Na bazi premera dela sastojine crnog bora u Lipovici, površine p= 0.1 ha i poznate starosti od 55 godina:

N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P. N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P.
1 26.1 1 45 21 3
2 26.6 1 46 25.9 1.3 1.8 2.2 2.2 1
3 22.8 1.3 2.3 1.6 1.6 1 47 25.5 18.1 13.3 1.6 1.7 1.2 2.7 2
4 18.2 1 48 29.6 19 13.3 2.7 2.2 1.6 2.2 2
5 28 1.6 2.1 1.1 3.3 1 49 22.6 17.9 14.1 1
6 32.5 23.1 1.2 2.4 2 3.4 1 50 / /
7 28.9 18.1 1 51 22.6 3
8 21.6 2 52 18.9 3
9 19.1 1 53 18.8 2
10 18.7 2 54 17.6 1
11 22.5 2 55 23 3
12 22.4 1 56 / /
13 21.6 2 57 25.6 1
14 27.9 1 58 30.2 20.3 14.3 3 1.9 1.4 3.8 2
15 30.1 19.1 14 1.8 1.4 3.1 3.1 1 59 25.9 2.4 1.6 1.9 2.4 2
16 20.3 2 60 30.7 21.9 14.7 1.6 2.5 2.2 3 1
17 30.4 20.9 1.9 2.2 2.5 2.3 2 61 25.2 21.2 13 1.1 1.8 2 2.6 3
18 27.3 19 14.6 1.7 2.3 2.1 1.6 2 62 21.2 2.5 1.6 0.6 1.4 1
19 17.1 18.2 14.4 2 63 28.7 22.1 14.2 2.3 1.4 1.8 3 1
20 24.5 1.9 1.6 1.8 1.8 1 64 17.7 1
21 22.8 1 65 25.9 21.5 14.7 2
22 22.1 1 66 31 23 15 2.2 2.1 2 3 2
23 27.8 2.1 1.1 2 2.2 1 67 27.1 19.8 13 1.5 1.9 2 3.1 1
24 16.1 3 68 26 21 14.3 3
25 19.9 2 69 29.8 20.2 13.1 3
26 13.4 2 70 21.8 19.4 14 3
27 20 2 71 20.7 18.3 12.9 1
28 33.3 22.8 1.8 2 2.6 3.5 1 72 24.6 19 13 1.8 1.7 2.8 2 2
29 21.7 1 73 / /
30 37.1 23.9 1 74 23.8 18 12.3 1
31 24.8 21.5 14.3 2 75 27.9 17.4 2
32 24.5 21.7 14.7 1 76 36 23.7 3
33 30.2 21.3 15 2 77 26.7 1
34 12.4 17.5 14.4 3 78 / /
35 22.4 2 79 26.3 2
36 24.2 2 80 16.6 1
37 27.8 1 81 32 22.5 2.7 2.8 1.9 3.7 1
38 / / 82 24 1
39 19 16.2 12.6 1 83 22.3 3
40 26.9 2.1 0.9 2.3 2.6 1 84 23 3
41 25.1 1.6 1.9 1.5 2.4 1 85 29 19.1 1.8 1.7 3.1 2.6 3
42 25.8 1.6 1.9 1.8 3.3 2 86 20.1 18.9 13.3 1
43 28.2 17.9 2.5 2.4 1.6 3 2 87 23.4 1.4 1.5 1.8 2.5 1
44 24.8 1.6 1.5 2.3 2.3 2 Suma 2005.6



Odrediti i analizirati sledeće elemente rasta i sastojinske izgrađenosti i po potrebi ih grafički predstaviti:
1. Srednje prečnike i visine;

    . Aritmetički srednji prečnik:
       \(\overline{d} = \frac{1}{n} \sum_{1}^{n}d=\)

    . Srednji prečnik po temeljnici:
       \(d_g = \sqrt\frac{\sum_{1}^{n}d^2}{n}=\sqrt\frac{\sum_{1}^{n}{50923.8}}{n}=\)

    . Srednji prečnik dominantnih stabala po temeljnici:
       \(D_g = \sqrt\frac{\sum_{1}^{n}D_{20\%}^2}{n_{20\%}}=\)

    . Aritmetička srednja visina:
       \(\overline{h} = \frac{1}{n} \sum_{1}^{n}h=\)

    . Srednja visina dominantnih stabala:
       \(H_g = \sqrt\frac{\sum_{1}^{n}H_{20\%}^2}{n_{20\%}}=\)

    . Visinsku krivu i krivu visina početka krošnje:

\(redova\qquad 60 x 65\qquad kolona\)