Na bazi premera dela sastojine crnog bora u Lipovici, površine p= 0.1 ha i poznate starosti od 55 godina:

N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P. N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P.
1 26 1 45 21.3 3
2 26.5 1 46 26.1 1.1 2 2.7 2.5 1
3 23 1.5 2.6 1.8 1.3 1 47 25.5 17.9 12.9 1.4 1.7 1.5 2.8 2
4 17.9 1 48 29.5 18.7 13.3 2.9 2.6 1.4 2.1 2
5 27.7 1.8 2 1.1 2.9 1 49 22.7 18.1 14.4 1
6 32.3 23.2 1.4 2.5 2 3.3 1 50 / /
7 28.8 18.2 1 51 22.9 3
8 21.7 2 52 18.8 3
9 19 1 53 19.4 2
10 18.7 2 54 17.8 1
11 22.6 2 55 22.6 3
12 22.5 1 56 / /
13 21.7 2 57 25.4 1
14 27.9 1 58 30.5 20.4 14.5 2.9 1.9 1.5 3.5 2
15 30 19 13.9 1.8 1.2 2.7 3.4 1 59 25.7 2.6 1.4 1.7 2 2
16 20.4 2 60 30.9 22.1 14.3 1.8 2.4 2.1 2.7 1
17 30.5 21.3 2.3 2.2 2.6 2.3 2 61 25 21.5 13.1 1 1.7 2.4 2.4 3
18 27 18.7 14.6 1.6 2.3 2.2 1.5 2 62 21.3 2.7 1.6 0.8 1.9 1
19 17 18.5 14.6 2 63 28.8 22 13.7 2.3 1.3 1.6 3 1
20 24.4 2.1 1.8 1.7 1.8 1 64 17.7 1
21 22.6 1 65 26 21.5 14.3 2
22 22 1 66 30.8 22.5 14.7 2.3 2.4 1.9 2.8 2
23 27.9 2.2 1.3 2.8 1.9 1 67 26.9 20.2 13 1.5 1.7 2.3 2.9 1
24 15.9 3 68 25.6 20.9 14.3 3
25 20.3 2 69 29.6 20.4 12.8 3
26 13.2 2 70 21.6 19.6 14 3
27 19.8 2 71 20.5 18 12.9 1
28 33.3 23 2 2.3 2.6 3.5 1 72 24.1 19.2 13 1.9 2 2.8 1.8 2
29 21.9 1 73 / /
30 36.8 24 1 74 23.7 18.1 12.2 1
31 24.7 21.4 14.1 2 75 28 17.6 2
32 24 22 15 1 76 35.9 23.3 3
33 30.5 21.4 15.1 2 77 26.5 1
34 12.2 17.5 14.2 3 78 / /
35 22.5 2 79 25.9 2
36 23.9 2 80 17.1 1
37 27.8 1 81 32 22.5 3 2.8 2.1 3.6 1
38 / / 82 23.8 1
39 19.2 16.2 12.6 1 83 22.4 3
40 27 2.5 0.8 2.2 2.7 1 84 23.2 3
41 25.1 2 1.7 1.4 2.3 1 85 29.4 19 2 2.1 3.2 2.9 3
42 25.8 1.7 1.8 2 3.6 2 86 19.7 18.7 12.9 1
43 28.2 17.5 2.8 2.1 1.4 2.9 2 87 23.5 1.8 1.3 1.9 2.1 1
44 24.6 1.6 1.6 2.3 2.7 2 Suma 2002.9



Odrediti i analizirati sledeće elemente rasta i sastojinske izgrađenosti i po potrebi ih grafički predstaviti:
1. Srednje prečnike i visine;

    . Aritmetički srednji prečnik:
       \(\overline{d} = \frac{1}{n} \sum_{1}^{n}d=\)

    . Srednji prečnik po temeljnici:
       \(d_g = \sqrt\frac{\sum_{1}^{n}d^2}{n}=\sqrt\frac{\sum_{1}^{n}{50778.73}}{n}=\)

    . Srednji prečnik dominantnih stabala po temeljnici:
       \(D_g = \sqrt\frac{\sum_{1}^{n}D_{20\%}^2}{n_{20\%}}=\)

    . Aritmetička srednja visina:
       \(\overline{h} = \frac{1}{n} \sum_{1}^{n}h=\)

    . Srednja visina dominantnih stabala:
       \(H_g = \sqrt\frac{\sum_{1}^{n}H_{20\%}^2}{n_{20\%}}=\)

    . Visinsku krivu i krivu visina početka krošnje:

\(redova\qquad 60 x 65\qquad kolona\)