Na bazi premera dela sastojine crnog bora u Lipovici, površine p= 0.1 ha i poznate starosti od 55 godina:

N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P. N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P.
1 26.3 1 45 20.9 3
2 26.5 1 46 26.1 1.3 2 2.2 2 1
3 22.9 1.3 2.3 2.1 1.6 1 47 25.5 18.3 13 1.4 1.9 1.4 2.5 2
4 17.9 1 48 29.7 18.5 13.4 2.7 2.3 1.8 2 2
5 27.6 2 2.1 1.2 3.1 1 49 22.3 18.1 14.3 1
6 32.2 23.3 1.6 2.2 2.3 3.1 1 50 / /
7 28.9 18 1 51 22.3 3
8 21.3 2 52 18.8 3
9 18.9 1 53 19.1 2
10 18.8 2 54 17.8 1
11 22.5 2 55 22.8 3
12 22.4 1 56 / /
13 22.2 2 57 25.3 1
14 27.7 1 58 30.5 20.5 14.4 2.8 1.8 1.5 3.8 2
15 29.9 19 13.6 2.1 1.6 3.2 3.3 1 59 25.9 2.5 1.7 1.9 1.9 2
16 20.3 2 60 30.9 21.9 14.5 2 2.5 2 3 1
17 30.4 21.1 1.9 2.2 2.4 2.5 2 61 25.3 21 13.2 1.2 2 2.4 2.4 3
18 27 19.1 14.8 1.7 2.2 2.1 1.5 2 62 21.4 2.4 1.6 0.6 1.8 1
19 16.7 18.1 14.6 2 63 28.9 22.2 14.1 2.3 1.2 1.8 2.7 1
20 24.4 2.2 1.9 1.8 1.6 1 64 17.9 1
21 22.9 1 65 25.8 21.5 14.4 2
22 22.2 1 66 30.8 22.8 14.7 2.1 1.9 2 2.7 2
23 27.5 2.2 1.3 2.3 2 1 67 26.8 20 13.1 1.8 1.6 2.1 3.1 1
24 15.8 3 68 25.9 21.1 14.7 3
25 20.1 2 69 29.8 20.2 13.1 3
26 13.1 2 70 21.8 19.6 13.8 3
27 19.9 2 71 20.8 18.2 13.2 1
28 33.1 22.9 1.9 2.1 2.7 3.7 1 72 24.3 19 13 2.2 1.6 2.6 1.9 2
29 21.6 1 73 / /
30 36.8 24 1 74 23.5 17.9 12.3 1
31 24.8 21.5 14.1 2 75 28.3 17.5 2
32 24.2 21.8 15.1 1 76 35.9 23.8 3
33 30.5 21.4 14.8 2 77 26.8 1
34 12.1 17.6 14 3 78 / /
35 22.5 2 79 26.3 2
36 24.1 2 80 17 1
37 27.6 1 81 31.4 22.7 2.9 2.9 2.3 3.6 1
38 / / 82 23.8 1
39 19.2 16.3 12.5 1 83 22.8 3
40 27.1 2.6 0.6 2.6 2.7 1 84 23.1 3
41 25.1 2 1.8 1.5 2.5 1 85 29.1 19 1.9 2.3 3.1 2.6 3
42 25.8 1.8 1.9 1.9 3.5 2 86 19.9 18.6 13 1
43 28.3 17.9 2.7 2.2 1.6 3.2 2 87 23.2 1.4 1.3 1.7 2.6 1
44 24.5 1.9 1.2 2.6 2.6 2 Suma 2002.1



Odrediti i analizirati sledeće elemente rasta i sastojinske izgrađenosti i po potrebi ih grafički predstaviti:
1. Srednje prečnike i visine;

    . Aritmetički srednji prečnik:
       \(\overline{d} = \frac{1}{n} \sum_{1}^{n}d=\)

    . Srednji prečnik po temeljnici:
       \(d_g = \sqrt\frac{\sum_{1}^{n}d^2}{n}=\sqrt\frac{\sum_{1}^{n}{50742.77}}{n}=\)

    . Srednji prečnik dominantnih stabala po temeljnici:
       \(D_g = \sqrt\frac{\sum_{1}^{n}D_{20\%}^2}{n_{20\%}}=\)

    . Aritmetička srednja visina:
       \(\overline{h} = \frac{1}{n} \sum_{1}^{n}h=\)

    . Srednja visina dominantnih stabala:
       \(H_g = \sqrt\frac{\sum_{1}^{n}H_{20\%}^2}{n_{20\%}}=\)

    . Visinsku krivu i krivu visina početka krošnje:

\(redova\qquad 60 x 65\qquad kolona\)