Na bazi premera dela sastojine crnog bora u Lipovici, površine p= 0.1 ha i poznate starosti od 55 godina:

N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P. N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P.
1 26.2 1 45 20.9 3
2 26.2 1 46 26 1.2 2.2 2.4 2.1 1
3 22.7 1.4 2.4 1.9 1.5 1 47 25.2 18.1 12.9 1.5 1.6 1.5 2.9 2
4 18.1 1 48 29.6 19 13.4 2.8 2.3 1.7 1.9 2
5 27.6 1.6 2.1 1.4 2.8 1 49 22.5 18.3 14.3 1
6 32 23.3 1.5 2.1 1.9 3.3 1 50 / /
7 28.8 18 1 51 22.7 3
8 21.7 2 52 18.9 3
9 18.8 1 53 18.8 2
10 18.7 2 54 17.6 1
11 22.5 2 55 23.1 3
12 22.3 1 56 / /
13 21.9 2 57 25.5 1
14 27.5 1 58 30.4 20.2 14.4 2.8 1.9 1.4 3.6 2
15 30.1 19 13.8 1.6 1.4 2.9 3.4 1 59 26 2.5 1.8 2 2.1 2
16 20.3 2 60 30.8 22 14.8 1.9 2.6 2 3 1
17 30.8 21 2 2.1 2.7 2.6 2 61 25.4 20.9 13 1.1 1.6 2.3 2.4 3
18 27.1 18.8 14.5 1.8 2.2 1.7 1.5 2 62 21.5 2.4 1.7 0.7 2.1 1
19 17.2 18.3 14.3 2 63 28.7 22 14 2.4 1.6 1.8 2.7 1
20 24.4 1.9 1.8 1.6 1.7 1 64 17.9 1
21 22.9 1 65 25.8 21.5 14.6 2
22 22.1 1 66 31 22.9 14.7 2.1 2.2 2.3 3 2
23 27.7 2.3 1.1 2.5 1.9 1 67 27 19.8 12.8 1.8 1.8 2.4 3 1
24 15.9 3 68 25.9 21.2 14.5 3
25 20.3 2 69 29.3 20.3 13.3 3
26 13.3 2 70 21.7 19.5 14.2 3
27 19.9 2 71 20.6 18.3 13.2 1
28 33.1 22.7 2 2.2 2.7 3.3 1 72 24.2 19.4 13.2 2.1 1.7 2.6 1.7 2
29 21.6 1 73 / /
30 36.6 23.8 1 74 23.4 18.2 12.6 1
31 24.6 21.6 14.3 2 75 28 17.6 2
32 24.1 21.7 14.8 1 76 36.2 23.5 3
33 30.4 21.2 14.9 2 77 26.6 1
34 12.3 17.9 14.5 3 78 / /
35 22.4 2 79 26.5 2
36 24.2 2 80 17.1 1
37 27.6 1 81 31.9 22.3 3 2.6 2.1 3.8 1
38 / / 82 24.1 1
39 19.4 16.6 12.8 1 83 22.3 3
40 27.1 2.6 0.8 2.5 2.7 1 84 22.7 3
41 24.6 2 2 1.6 2.5 1 85 28.9 19.1 1.8 2 3 2.5 3
42 25.9 1.6 1.9 2 3.3 2 86 20 18.6 13.1 1
43 28.8 17.6 2.4 2.4 1.5 3 2 87 23.3 1.7 1.5 1.7 2.5 1
44 24.6 1.8 1.5 2.2 2.7 2 Suma 2002.3



Odrediti i analizirati sledeće elemente rasta i sastojinske izgrađenosti i po potrebi ih grafički predstaviti:
1. Srednje prečnike i visine;

    . Aritmetički srednji prečnik:
       \(\overline{d} = \frac{1}{n} \sum_{1}^{n}d=\)

    . Srednji prečnik po temeljnici:
       \(d_g = \sqrt\frac{\sum_{1}^{n}d^2}{n}=\sqrt\frac{\sum_{1}^{n}{50737.59}}{n}=\)

    . Srednji prečnik dominantnih stabala po temeljnici:
       \(D_g = \sqrt\frac{\sum_{1}^{n}D_{20\%}^2}{n_{20\%}}=\)

    . Aritmetička srednja visina:
       \(\overline{h} = \frac{1}{n} \sum_{1}^{n}h=\)

    . Srednja visina dominantnih stabala:
       \(H_g = \sqrt\frac{\sum_{1}^{n}H_{20\%}^2}{n_{20\%}}=\)

    . Visinsku krivu i krivu visina početka krošnje:

\(redova\qquad 60 x 65\qquad kolona\)