Na bazi premera dela sastojine crnog bora u Lipovici, površine p= 0.1 ha i poznate starosti od 55 godina:

N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P. N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P.
1 26.3 1 45 20.9 3
2 26.5 1 46 26 1.3 1.8 2.6 2.1 1
3 22.6 1.7 2.1 1.9 1.5 1 47 25.4 17.9 12.9 1.7 1.5 1.2 2.7 2
4 18 1 48 29.4 18.6 13.4 2.5 2.3 1.5 2 2
5 27.8 1.7 2.3 1.1 3 1 49 22.4 18.3 14.4 1
6 32.3 23 1.5 2.4 2.1 3.3 1 50 / /
7 28.7 18.1 1 51 22.8 3
8 21.4 2 52 18.7 3
9 18.7 1 53 19.3 2
10 18.7 2 54 17.6 1
11 22.6 2 55 22.7 3
12 22.4 1 56 / /
13 21.9 2 57 25.6 1
14 28 1 58 30.5 20.4 14.3 2.9 2 1.4 3.8 2
15 29.9 19.3 13.9 1.6 1.4 2.8 3.4 1 59 25.9 2.7 1.4 1.9 2.2 2
16 20.1 2 60 30.5 22.3 14.5 2 2.5 2 2.9 1
17 30.6 20.9 2 1.8 2.6 2.4 2 61 25.1 21.5 12.9 1.1 1.5 2.6 2.7 3
18 26.9 18.8 14.5 1.5 2.4 1.8 1.7 2 62 21.6 2.4 1.7 0.8 1.8 1
19 16.9 18.2 14.6 2 63 29 22 14 2.2 1.3 2 2.9 1
20 24.6 2.1 1.5 2 1.6 1 64 17.9 1
21 22.7 1 65 26.2 21.5 14.4 2
22 22.1 1 66 30.8 22.6 14.5 2 2.2 2.3 3 2
23 27.6 2 1.2 2.3 2.2 1 67 27 19.9 13.2 1.7 1.5 2.2 3 1
24 15.9 3 68 25.8 21.2 14.4 3
25 20.1 2 69 29.8 20.1 13.4 3
26 13.4 2 70 21.7 19.4 13.8 3
27 20 2 71 20.5 17.9 13 1
28 33.3 23.1 1.9 2.2 2.7 3.5 1 72 24.4 19.5 13.2 2 1.9 2.7 1.8 2
29 22 1 73 / /
30 36.8 23.6 1 74 23.7 18.1 12 1
31 24.9 21.4 14.4 2 75 27.8 17.8 2
32 24.2 22.1 14.8 1 76 36 23.6 3
33 30.6 21.2 15 2 77 26.6 1
34 12 17.8 14.2 3 78 / /
35 22.2 2 79 26.3 2
36 24.3 2 80 16.7 1
37 27.7 1 81 31.9 22.8 3.1 2.8 2 3.5 1
38 / / 82 24.1 1
39 19.3 16.2 12.7 1 83 22.4 3
40 27.3 2.6 1 2.4 2.7 1 84 23.3 3
41 24.8 1.7 1.8 1.5 2.4 1 85 28.7 19 2.1 2 2.9 2.8 3
42 25.5 1.7 1.7 1.9 3.3 2 86 20 18.6 13.1 1
43 28.3 17.8 2.6 2.4 1.5 3 2 87 23.2 1.6 1.5 1.6 2.4 1
44 24.9 1.7 1.4 2.6 2.7 2 Suma 2003



Odrediti i analizirati sledeće elemente rasta i sastojinske izgrađenosti i po potrebi ih grafički predstaviti:
1. Srednje prečnike i visine;

    . Aritmetički srednji prečnik:
       \(\overline{d} = \frac{1}{n} \sum_{1}^{n}d=\)

    . Srednji prečnik po temeljnici:
       \(d_g = \sqrt\frac{\sum_{1}^{n}d^2}{n}=\sqrt\frac{\sum_{1}^{n}{50794.06}}{n}=\)

    . Srednji prečnik dominantnih stabala po temeljnici:
       \(D_g = \sqrt\frac{\sum_{1}^{n}D_{20\%}^2}{n_{20\%}}=\)

    . Aritmetička srednja visina:
       \(\overline{h} = \frac{1}{n} \sum_{1}^{n}h=\)

    . Srednja visina dominantnih stabala:
       \(H_g = \sqrt\frac{\sum_{1}^{n}H_{20\%}^2}{n_{20\%}}=\)

    . Visinsku krivu i krivu visina početka krošnje:

\(redova\qquad 60 x 65\qquad kolona\)