Na bazi premera dela sastojine crnog bora u Lipovici, površine p= 0.1 ha i poznate starosti od 55 godina:

N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P. N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P.
1 26 1 45 20.9 3
2 26.5 1 46 26.2 0.8 1.9 2.3 2.5 1
3 22.6 1.5 2 1.9 1.4 1 47 25.3 18 12.9 1.6 1.8 1.4 2.9 2
4 18 1 48 29.6 18.5 13.4 3 2.2 1.7 1.9 2
5 27.9 1.6 2.3 1.2 2.9 1 49 22.5 18.2 14 1
6 32.3 23.5 1.4 2.3 2 3.1 1 50 / /
7 29 18.2 1 51 22.9 3
8 21.6 2 52 18.6 3
9 18.8 1 53 19.1 2
10 19 2 54 17.4 1
11 22.9 2 55 22.9 3
12 22.6 1 56 / /
13 21.8 2 57 25.4 1
14 27.8 1 58 30.4 19.9 14.4 3 1.9 1.4 3.7 2
15 29.9 19.2 13.9 1.7 1.7 2.9 3.1 1 59 25.8 2.6 1.4 1.7 2.4 2
16 20.1 2 60 30.9 22.2 14.8 1.8 2.5 2 3.1 1
17 30.7 21 2 1.9 2.4 2.7 2 61 25.1 21.1 13.1 1 1.7 2.4 2.4 3
18 27.1 19 14.5 1.8 2.1 2.1 1.3 2 62 21.4 2.4 1.8 1 1.8 1
19 16.7 18.1 14.3 2 63 28.8 22.1 14 2.3 1.4 1.7 2.8 1
20 24.6 2.1 2 1.7 1.7 1 64 17.9 1
21 22.8 1 65 25.9 21.3 14.3 2
22 22 1 66 31 22.8 14.9 2.1 2 1.9 3.1 2
23 27.8 2.4 1.3 2.6 2.2 1 67 27.1 20.2 12.9 1.7 1.8 2 3.3 1
24 16 3 68 25.8 21.1 14.7 3
25 20.1 2 69 29.5 20.3 13 3
26 13.2 2 70 21.9 19.5 14.1 3
27 20.1 2 71 20.7 18.3 13 1
28 33.4 23 2 2 2.5 3.3 1 72 24.5 19.3 13.2 2.2 1.5 2.7 2.1 2
29 21.7 1 73 / /
30 37 24 1 74 23.7 18.1 12 1
31 24.8 21.7 14.2 2 75 27.6 17.8 2
32 24.1 21.8 14.8 1 76 36 23.6 3
33 30.3 21.5 14.5 2 77 26.7 1
34 12.2 17.9 14.6 3 78 / /
35 22.4 2 79 26.4 2
36 24.1 2 80 16.7 1
37 27.7 1 81 31.8 22.8 2.8 2.6 2.2 3.8 1
38 / / 82 23.7 1
39 19.4 16.2 12.5 1 83 22.4 3
40 27.2 2.6 1.2 2.6 2.6 1 84 22.9 3
41 24.7 1.9 1.7 1.5 2.6 1 85 29.2 19 1.9 1.9 3.1 2.7 3
42 25.9 1.6 1.8 1.6 3.6 2 86 19.9 18.8 13.1 1
43 28.4 17.6 2.8 2.4 1.4 3 2 87 23.2 1.6 1.3 1.7 2.5 1
44 24.8 1.8 1.5 2.3 2.5 2 Suma 2003.7



Odrediti i analizirati sledeće elemente rasta i sastojinske izgrađenosti i po potrebi ih grafički predstaviti:
1. Srednje prečnike i visine;

    . Aritmetički srednji prečnik:
       \(\overline{d} = \frac{1}{n} \sum_{1}^{n}d=\)

    . Srednji prečnik po temeljnici:
       \(d_g = \sqrt\frac{\sum_{1}^{n}d^2}{n}=\sqrt\frac{\sum_{1}^{n}{50840.99}}{n}=\)

    . Srednji prečnik dominantnih stabala po temeljnici:
       \(D_g = \sqrt\frac{\sum_{1}^{n}D_{20\%}^2}{n_{20\%}}=\)

    . Aritmetička srednja visina:
       \(\overline{h} = \frac{1}{n} \sum_{1}^{n}h=\)

    . Srednja visina dominantnih stabala:
       \(H_g = \sqrt\frac{\sum_{1}^{n}H_{20\%}^2}{n_{20\%}}=\)

    . Visinsku krivu i krivu visina početka krošnje:

\(redova\qquad 60 x 65\qquad kolona\)