Na bazi premera dela sastojine crnog bora u Lipovici, površine p= 0.1 ha i poznate starosti od 55 godina:

N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P. N d[cm] h [m] ld [m] r1 [m] r2 [m] r3 [m] r4 [m] B.P.
1 25.9 1 45 21 3
2 26.6 1 46 26.1 1.4 2 2.4 2.3 1
3 22.8 1.7 2.4 1.7 1.4 1 47 25.4 17.9 12.9 1.3 1.6 1.3 2.5 2
4 17.8 1 48 29.7 18.8 13.2 2.7 2.3 1.7 2.1 2
5 27.5 1.6 2.4 1 3 1 49 22.8 18.4 14.1 1
6 32.4 23.6 1.5 2.3 2.2 3.4 1 50 / /
7 29 18.1 1 51 22.8 3
8 21.4 2 52 18.9 3
9 19 1 53 19 2
10 18.9 2 54 17.6 1
11 22.6 2 55 22.7 3
12 22.5 1 56 / /
13 21.8 2 57 25.6 1
14 27.9 1 58 30.2 20.2 14.1 2.9 1.6 1.2 3.9 2
15 30.2 18.9 14.3 1.5 1.4 2.8 3.1 1 59 26 2.5 1.5 2.1 2.2 2
16 20 2 60 30.4 22 14.6 1.6 2.5 2.4 3 1
17 30.4 21.1 2.1 1.8 2.4 2.5 2 61 24.9 21.1 12.9 1.3 1.9 2.4 2.5 3
18 27 19.2 14.5 1.6 2.6 1.8 1.9 2 62 21.3 2.4 1.6 0.8 1.8 1
19 17.2 17.8 14.5 2 63 28.6 22.2 14.2 2.4 1.3 1.7 2.9 1
20 24.7 2.1 1.7 1.7 1.8 1 64 18 1
21 22.8 1 65 26 21.4 14.2 2
22 22 1 66 30.9 22.9 15 2.4 2.4 2.1 3 2
23 27.7 2.2 1.3 2.4 2.2 1 67 27 19.9 13 1.5 1.7 2.2 3.1 1
24 16 3 68 26 21.2 14.3 3
25 20.3 2 69 29.4 20.1 13.4 3
26 13.1 2 70 21.8 19.5 14 3
27 20 2 71 20.6 18.1 12.8 1
28 33.1 22.9 2.1 2 2.6 3.4 1 72 24.3 19.4 13 2.1 1.7 2.8 1.8 2
29 21.8 1 73 / /
30 36.9 23.6 1 74 23.6 18.2 12.3 1
31 24.8 21.7 14.6 2 75 28.3 17.7 2
32 24.2 22 15.1 1 76 35.7 23.4 3
33 30.3 21.6 15.1 2 77 26.7 1
34 12.3 17.5 14.6 3 78 / /
35 22.2 2 79 26.4 2
36 24 2 80 16.6 1
37 27.7 1 81 31.9 22.3 2.8 2.8 2 4 1
38 / / 82 23.9 1
39 19.4 16.2 12.5 1 83 22.2 3
40 27 2.5 0.8 2.7 2.9 1 84 22.9 3
41 25 2 1.9 1.5 2.3 1 85 29 18.9 2.1 1.9 3 2.5 3
42 25.9 1.6 1.6 2 3.3 2 86 19.6 18.7 13.3 1
43 28.4 17.9 2.5 2.4 1.4 3.3 2 87 23.3 1.4 1.5 1.7 2.6 1
44 24.6 1.5 1.7 2.4 2.7 2 Suma 2002.2



Odrediti i analizirati sledeće elemente rasta i sastojinske izgrađenosti i po potrebi ih grafički predstaviti:
1. Srednje prečnike i visine;

    . Aritmetički srednji prečnik:
       \(\overline{d} = \frac{1}{n} \sum_{1}^{n}d=\)

    . Srednji prečnik po temeljnici:
       \(d_g = \sqrt\frac{\sum_{1}^{n}d^2}{n}=\sqrt\frac{\sum_{1}^{n}{50740.14}}{n}=\)

    . Srednji prečnik dominantnih stabala po temeljnici:
       \(D_g = \sqrt\frac{\sum_{1}^{n}D_{20\%}^2}{n_{20\%}}=\)

    . Aritmetička srednja visina:
       \(\overline{h} = \frac{1}{n} \sum_{1}^{n}h=\)

    . Srednja visina dominantnih stabala:
       \(H_g = \sqrt\frac{\sum_{1}^{n}H_{20\%}^2}{n_{20\%}}=\)

    . Visinsku krivu i krivu visina početka krošnje:

\(redova\qquad 60 x 65\qquad kolona\)